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1736. Latest Time by Replacing Hidden Digits

You are given a string time in the form of hh:mm, where some of the digits in the string are hidden (represented by ?).

The valid times are those inclusively between 00:00 and 23:59.

Return the latest valid time you can get fromtimeby replacing the hidden digits.

Example 1:

Input: time = "2?:?0" Output: "23:50" Explanation: The latest hour beginning with the digit '2' is 23 and the latest minute ending with the digit '0' is 50. 

Example 2:

Input: time = "0?:3?" Output: "09:39" 

Example 3:

Input: time = "1?:22" Output: "19:22" 

Constraints:

• time is in the format hh:mm.
• It is guaranteed that you can produce a valid time from the given string.

Solutions (Rust)

1. Solution

implSolution{pubfnmaximum_time(time:String) -> String{letmut time = time.into_bytes();match(time[0], time[1]){(b'?',b'?') => { time[0] = b'2'; time[1] = b'3';}(b'?', t1)if t1 < b'4' => time[0] = b'2',(b'?', t1) => time[0] = b'1',(b'2',b'?') => time[1] = b'3',(t0,b'?') => time[1] = b'9',(t0, t1) => (),}if time[3] == b'?'{ time[3] = b'5';}if time[4] == b'?'{ time[4] = b'9';}String::from_utf8(time).unwrap()}}